So I have a feeling that doing math means constructing models, both physical and abstract. It’s not about the questions and answers, but about the pictures we make in our heads. Once we have a good picture, there are lots of questions for which we can find answers.

As a mathematician, I start wondering about how much grass is available for the goat to eat? How far can the goat reach? I’m sure you can figure out that the goat can reach all the grass within a circle centered at the stake in the ground. The radius of the circle is the length of the tether. How do I know that this is a circle? Because one definition of a circle is the set of points equidistant from a given point. The given point is the stake, and all the points at the farthest reach of the goat are the length of the tether (and the distance the goat can stretch its neck) from the stake.

The other aspect of an abstract model is that I am not interested in the actual length of the tether, so I use a variable to represent that length; I’ll use t. Now, it does not matter whether the goat is on a tether that is 5 feet long, or 18 feet long. I can even consider a tether that is a mile long, if I assume the field is really big and has nothing in the way that the tether could get wrapped around. (I’ll think about those possibilities later.)
Why is the model important? Because it allows me to answer lots and lots of questions about the situation! Here are a few:
1. If the tether is 8 feet long, what is the area in which the goat can graze?
2. Suppose we want to fence in the grazing area, just in case the goat chews through the tether. How many feet of fence would we need if the tether were 10 feet long?
3. If a goat needs 50 square feet of grazing space each day, how long should I make the tether?
Since I have the model of a circle in mind, I can answer all these questions by using what I know about circles: The area within a circle is equal to pi times the square of the radius, and the perimeter or circumference of the circle is equal to pi times twice the radius, or pi times the diameter.
Here’s another question: Suppose the tether were 10 feet long, and that the goat wanders randomly within its grazing area. What percentage of the time is the goat within five feet of the stake? For this question, I need to modify my model slightly.

Now, being a mathematician, this is not where the problem ends. Answer getting is not the purpose. Completely understanding the model is what this is all about. So, I start generalizing a little. Remember that I was going to use a variable for the length of the tether? So the question now becomes “what percent of the time does the goat spend within a region halfway to the edge of his grazing area?” Using the same formula as above, but using t for the length of the tether, and ½t for half that length, we have:
(½t)^2*pi / t^2*pi
= ¼ t^2 / t^2
= ¼ or 25%
In other words, no matter how long the tether, the area of the inner circle is always 25% of the area of the outer circle, if the radius of the inner circle is ½ the radius of the outer circle. I keep jumping between the physical model of the goat and the abstract model of the concentric circles.
As I write this, I am thinking about my model, and I realize that if the inner circle is ¼ the area of the outer circle, then I can divide the circle into quarters differently than I usually do.

Here are some variations on the inital situation that also require some changes to the model. (I'm going to have to explore these in a later post.) What if the tether were staked along the side of a building? What if the stake was at the corner of a building? What if the tether was long enough so that the goat could walk all the way around the building?
I am beginning to feel like a goat on a really long tether, exploring the outer reaches of my model's boundaries!
By the way, here are the answers to the questions above: (I apologize for the format; I am still learning the capabilities of posting pictures and math symbols here.)
1. 64*pi which is about 201.062 square feet of grass
2. 20*pi which is about 62.832 feet of fence
3. sqrt(50/pi) or approximately 3.989 foot long tether
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